Q150 / 180 · KCET 2009 · Physics
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of $20 \mathrm{~m}$ is


- A$225 \mathrm{~J}$
- Correct answerB$200 \mathrm{~J}$
- C$400 \mathrm{~J}$
- D$175 \mathrm{~J}$
Solution
Word done $W=$ Area ABCEFDA $=$ Area $\mathrm{ABCD}+$ Area CEFD

$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$ $=125+75=200 \mathrm{~J}$

$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$ $=125+75=200 \mathrm{~J}$
Hence, the correct answer is option: 'B'.