Q150 / 180 · KCET 2009 · Physics

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of $20 \mathrm{~m}$ is
Figure

  • A
    $225 \mathrm{~J}$
  • Correct answer
    B
    $200 \mathrm{~J}$
  • C
    $400 \mathrm{~J}$
  • D
    $175 \mathrm{~J}$

Solution

Word done $W=$ Area ABCEFDA $=$ Area $\mathrm{ABCD}+$ Area CEFD
Figure
$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$ $=125+75=200 \mathrm{~J}$

Hence, the correct answer is option: 'B'.

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