Q9 / 160 · AP EAMCET 2023 (16 May Shift 1) · Chemistry

The weight percentage of $\mathrm{C}$ and $\mathrm{H}$ in a hydrocarbon is in the ratio of $4: 1$. What is its empirical formula?

  • A
    $\mathrm{CH}$
  • B
    $\mathrm{CH}_2$
  • Correct answer
    C
    $\mathrm{CH}_3$
  • D
    $\mathrm{CH}_4$

Solution

$\mathrm{M}(\mathrm{c})=12.01, \mathrm{M}(\mathrm{H})=1.0$ $\mathrm{m}(\mathrm{c})=4 \times \mathrm{m}(\mathrm{H})$ (Given) If $\mathrm{n}(\mathrm{c})=1$ and $\mathrm{n}(\mathrm{H})=3$ $\Rightarrow \mathrm{m}(\mathrm{c})=12.01$ and $\mathrm{m}(\mathrm{H})=3$ and $\mathrm{C}: \mathrm{H}$ mass ratio $=4: 1$ $\Rightarrow$ Empirical formula $=\mathrm{CH}_3$.

Hence, the correct answer is option: 'C'.

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