The wavelength of the first line of Balmer series of hydrogen atom is $\lambda$, what will be the wavelength of the same line in doubly ionized lithium?

• A

  $\frac{\lambda}{2}$
• Correct answer
  B

  $\frac{\lambda}{9}$
• C

  $\frac{\lambda}{8}$
• D

  $\frac{\lambda}{27}$

Hence, the correct answer is option: 'B'.