The wavelength of a photon and de-Broglie wavelength an electron have the same value. Given that $v$ is the speed of electron and $c$ is the velocity of light. $E_e, E_p$ is the kinetic energy of electron and energy of photon respectively while $p_e, p_h$ is the momentum of electron and photon respectively. Then which of the following relation is correct?

• Correct answer
  A

  $\frac{E_e}{E_p}=\frac{v}{2c}$
• B

  $\frac{E_e}{E_p}=\frac{2c}{v}$
• C

  $\frac{p_e}{p_h}=\frac{c}{2v}$
• D

  $\frac{p_e}{p_h}=\frac{2c}{v}$

Hence, the correct answer is option: 'A'.