Q2 / 90 · JEE Main 2019 (12 Jan Shift 2) · Chemistry

The volume strength of $1 M H_{2} O_{2}$ is:

(Molar mass of $H_{2} O_{2} = 34 g mol^{- 1}$ )

A
$5.6$
B
$22.4$
Correct answer
C
$11.2$
D
$16.8$

Solution

H_{2} O_{2} \to H_{2} O +

\frac{1}{2} O_{2}

Volume strength = 11.2 \times Molarity

= 11.2 \times 1

= 11.2

Hence, the correct answer is option: 'C'.

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