Q58 / 180 · KCET 2022 · Chemistry
The volume of $2.8 \mathrm{~g}$ of $\mathrm{CO}$ at $27^{\circ} \mathrm{C}$ and 0.821 atm pressure is
$$
\left(R=0.08210 \text { L. atm K }{ }^{-1} \mathrm{~mol}^{-1}\right)
$$
- A1.5 litres
- Correct answerB3 litres
- C30 litres
- D0.3 litres
Solution
Given, amount of $\mathrm{CO}=2.8 \mathrm{~g}$
Temperature $=27^{\circ} \mathrm{C}$
Pressure $=0.821 \mathrm{~atm}$
$R=0.08210 \mathrm{~L} \mathrm{~atm} \mathrm{~K}{ }^{-1} \mathrm{~mol}^{-1}$
We know that, $p V=R T$
$\therefore \quad V=\frac{R T}{p}=\frac{0.0821 \times 300}{0.821}=30 \mathrm{~L}$
$\therefore 28 \mathrm{~g}$ of CO occupy volume $30 \mathrm{~L}$
$\therefore 2.8 \mathrm{~g}$ of CO occupy volume $=\frac{30 \times 2.8}{28}=3 \mathrm{~L}$
Hence, the correct answer is option: 'B'.