The voltage $V(t)$ across a capacitor of capacitance $C$ discharging through a resistance $R$ is given by $V(t)=V_0 e^{-t / R C}$. The initial voltage $V_0$ is $10.00 \pm 0.02 \mathrm{~V}, R=100.0$ $\pm 0.1 \% \mathrm{M} \Omega$ and $C=1.00 \mu \mathrm{~F}$. The circuit is closed and subsequently disconnected after $100 \pm 1$ seconds. The final voltage is best represented as

• A

  $2.71 \pm 0.01 \mathrm{~V}$
• B

  $3.67 \pm 0.003 \mathrm{~V}$
• Correct answer
  C

  $3.67 \pm 0.05 \mathrm{~V}$
• D

  $3.67 \pm 0.37 \mathrm{~V}$

Hence, the correct answer is option: 'C'.