Q70 / 160 · AP EAMCET 2019 (21 Apr Shift 2) · Mathematics

The vector equation of the plane passing through the points (1,-2,5), (0,-5,-1) and (-3,5,0) is

  • Correct answer
    A
    r¯=(1-λ-4μ)i¯-(2+3λ-7μ)j¯+(5-6λ-5μ)k¯
  • B
    r¯=(1+λ+4μ)i¯-(2-3λ+7μ)j¯+(5-6λ-5μ)k¯
  • C
    r¯=(1-λ+4μ)i¯-(2+3λ+7μ)j¯+(5-6λ+5μ)k¯
  • D
    r¯=(1+λ-4μ)i¯+(2+3λ-7μ)j¯+(5+6λ-5μ)k¯

Solution

The vectors of the points are,

a→=i^-2j^+5k^

b→=-5j^-k^

c→=-3i^+5j^

The vector equation of the plane,

r→=a→+λ(b→-a→)+μ(c→-a→)

⇒r→=(i^-2j^+5k^)+λ[(-5j^-k^)-(i^-2j^+5k^)]+μ[(-3i^+5j^)-(i^-2j^+5k^)]

⇒r→=i^-2j^+5k^+λ(-i^-3j^-6k^)+μ(-4i^+7j^-5k^)

⇒r→=(1-λ-4μ)i^-(2+3λ-7μ)j^+(5-6λ-5μ)k^

Hence, the correct answer is option: 'A'.

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