Q39 / 160 · NTA Abhyas (NEET) 2020 · Chemistry · Solutions
The vapour pressures of pure liquids A and B are 400 and 600 mmHg, respectively at 298 K. On mixing the two liquids, the sum of their initial volumes is equal to the volume of the final mixture. The mole fractional of liquid B is 0.5 in the mixture. The vapour pressure of the final solution, the mole fraction of components A and B in vapour phase, respectively are
- A500 mm Hg, 0.5, 0.5
- B450 mm Hg, 0.4, 0.6
- C450 mm Hg, 0.5, 0.5
- Correct answerD500 mm Hg, 0.4, 0.6
Solution
Let and be the mole fraction of liquid A and B in the mixture.
Given,
Now, mole fraction of A in vapour,
Hence
and mole fraction of B in vapour,
Given,
Now, mole fraction of A in vapour,
Hence
and mole fraction of B in vapour,
Hence, the correct answer is option: 'D'.