Q66 / 199 · NEET 2008 (Mains) · Chemistry
The values of $K_{P 1}$ and $K_{\mathrm{P} 2}$ for the reactions
$$
\begin{aligned}
& X \rightleftharpoons Y+Z . \\
& A \rightleftharpoons 2 B . .
\end{aligned}
$$
are in ratio of 9:1. If degree of dissociation of $X$ and $\mathrm{A}$ be equal, then total pressure at equilibrium (1) and (2) are in the ratio
- A$1: 1$
- B$3: 1$
- C$1: 9$
- Correct answerD$36: 1$
Solution

$$ \begin{aligned} & \text { or } \frac{\mathrm{K}_{\mathrm{P}_1}}{\mathrm{~K}_{\mathrm{P}_2}}=\frac{\mathrm{P}}{4 \mathrm{P}^{\prime}} \quad \text { or } \quad \frac{9}{1}=\frac{\mathrm{P}}{4 \mathrm{P}^{\prime}} \\ & \text { or } \frac{\mathrm{P}^{\prime}}{\mathrm{P}}=36: 1 \end{aligned} $$
Hence, the correct answer is option: 'D'.