Q77 / 200 · Manipal (MET) 2012 · Mathematics

The value of $[\mathbf{a} \mathbf{a}+\mathbf{b} \mathbf{a}+\mathbf{b}+\mathbf{c}]$ is

  • A
    $[\mathrm{abc}]^2$
  • Correct answer
    B
    $[\mathbf{a b c}$]
  • C
    $2[\mathbf{a b} \mathbf{c}]$
  • D
    $3[\mathbf{a b c}]$

Solution

Now, $\left[\begin{array}{lll}\mathbf{a} & \mathbf{a}+\mathbf{b} & \mathbf{a}+\mathbf{b}+\mathbf{c}\end{array}\right]$ $\begin{aligned} & =[\mathbf{a} \times(\mathbf{a}+\mathbf{b})] \cdot(\mathbf{a}+\mathbf{b}+\mathbf{c}) \\ & =(\mathbf{a} \times \mathbf{b}) \cdot(\mathbf{a}+\mathbf{b}+\mathbf{c})=(\mathbf{a} \times \mathbf{b}) \cdot \mathbf{c} \\ & =[\mathbf{a} \mathbf{b} \mathbf{c}] \end{aligned}$

Hence, the correct answer is option: 'B'.

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