Q53 / 150 · MHT CET 2010 · Mathematics
The value of $\lim _{x \rightarrow 0} \frac{15^{x}-5^{x}-3^{x}+1}{1-\cos 2 x}$ is
- Correct answerA$\frac{(\log 3)(\log 5)}{2}$
- B$2(\log 3)(\log 5)$
- C$\frac{\log 3+\log 5}{2}$
- DNone of these
Solution
$\lim _{x \rightarrow 0} \frac{15^{x}-5^{x}-3^{x}+1}{1-\cos 2 x}$
$=\lim _{x \rightarrow 0} \frac{\left(3^{x}-1\right)\left(5^{x}-1\right)}{1-1+2 \sin ^{2} x}$
$\quad=\lim _{x \rightarrow 0}\left(\frac{3^{x}-1}{x}\right)\left(\frac{5^{x}-1}{x}\right)\left(\frac{x^{2}}{2 \sin ^{2} x}\right)$
$=\frac{1}{2}(\log 3)(\log 5) \cdot 1$
$\quad\left[\because \lim _{x \rightarrow 0}\left(\frac{a^{x}-b^{x}}{x}\right)=\log \left(\frac{a}{b}\right)\right]$
Hence, the correct answer is option: 'A'.