Q70 / 160 · WBJEE 2010 · Mathematics

The value of $\frac{\cot 54^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ}}{\cot 70^{\circ}}$ is

  • A
    0
  • Correct answer
    B
    2
  • C
    3
  • D
    1

Solution

Hints: $\frac{\cot 54^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ}}{\cot 70^{\circ}}=\frac{\tan 36^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ}}{\tan 20^{\circ}}=1+1=2$

Hence, the correct answer is option: 'B'.

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