Q76 / 160 · WBJEE 2009 · Mathematics

The value of $\left(\frac{1}{\log _3 12}+\frac{1}{\log _4 12}\right)$ is

A
0
B
$\frac{1}{2}$
Correct answer
C
1
D
2

Solution

Hints : $\log _{12} 3+\log _{12} 4=\log _{12} 12=1$

Hence, the correct answer is option: 'C'.

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