Q125 / 150 · MHT CET 2016 · Physics

The value of gravitational acceleration $g$ at a height $h$ above the earth's surface is $\frac{g}{4}$ then (R = radius of earth)

Correct answer
A
$h = R$
B
$h = \frac{R}{2}$
C
$h = \frac{R}{3}$
D
$h = \frac{R}{4}$

Solution

g^{'} = g {(\frac{R}{R + h})}^{2}

When

g^{'} = \frac{g}{4}

then.

\frac{g}{4} = g \times {(\frac{R}{R + h})}^{2} \Rightarrow \frac{1}{2} = \frac{R}{R + h}

∴ 2 R = R + h \Rightarrow R = h

Hence, the correct answer is option: 'A'.

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