Q147 / 160 · WBJEE 2010 · Physics

The value of ' $\lambda$ ' for which the two vectors $\vec{a}=5 \hat{i}+\lambda \hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-2 \hat{j}+\hat{k}$ are perpendicular to each other is

  • A
    2
  • B
    -2
  • Correct answer
    C
    3
  • D
    -3

Solution

Hints : For $\vec{a} \perp \vec{b}$ $\begin{aligned} & \vec{a} \cdot \vec{b}=0 \\ & \text { i.e., } 5-2 \lambda+1=0 \\ & \lambda=3 \end{aligned}$

Hence, the correct answer is option: 'C'.

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