Q71 / 180 · NEET 2015 (Phase 2) · Chemistry

The vacant space in bcc lattice unit cell is:

  • A
    26%
  • B
    48%
  • C
    23%
  • Correct answer
    D
    32%

Solution

Step 1: Packing efficiency of BCC unit cell - Packing efficiency of BCC unit cell is given by, \(\begin{aligned} & \text { Packing efficiency }=\frac{\text { Volume occupied by two spheres } \times 100}{\text { Volume of unit cell }} \\ & =\frac{2 \times \frac{4}{3} \pi r^3 \times 100}{a^3} \\ & =68 \% \end{aligned}\) - The \(\%\) volume occupied by atoms in a unit cell is \(68 \%\) Step 2: % Vacant space in BCC unit cell - % vacant space is given by, \(\begin{aligned} & \% \text { Vacant space }=100-\% \text { of the volume occupied by atoms } \\ & =100-68 \\ & =32 \% \end{aligned}\) - % Vacant space is \(32 \%\)

Hence, the correct answer is option: 'D'.

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