Q88 / 125 · BITSAT 2011 · Physics

The two vectors $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ are drawn from a common point and $\overrightarrow{\mathrm{C}}=\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}},$ then angle between $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ is - (1) $90^{\circ}$ if $\mathrm{C}^{2}=\mathrm{A}^{2}+\mathrm{B}^{2}$ (2) greater than $90^{\circ}$ if $\mathrm{C}^{2}<\mathrm{A}^{2}+\mathrm{B}^{2}$ (3) greater than $90^{\circ}$ if $\mathrm{C}^{2}>\mathrm{A}^{2}+\mathrm{B}^{2}$ (4) less than $90^{\circ}$ if $\mathrm{C}^{2}>\mathrm{A}^{2}+\mathrm{B}^{2}$ Correct options are -

  • A
    1,2
  • B
    1,2,3,4
  • C
    2,3,4
  • Correct answer
    D
    1,2,4

Hence, the correct answer is option: 'D'.

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