Q88 / 125 · BITSAT 2011 · Physics
The two vectors $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ are drawn from a common point and $\overrightarrow{\mathrm{C}}=\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}},$ then angle
between $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ is -
(1) $90^{\circ}$ if $\mathrm{C}^{2}=\mathrm{A}^{2}+\mathrm{B}^{2}$
(2) greater than $90^{\circ}$ if $\mathrm{C}^{2}<\mathrm{A}^{2}+\mathrm{B}^{2}$
(3) greater than $90^{\circ}$ if $\mathrm{C}^{2}>\mathrm{A}^{2}+\mathrm{B}^{2}$
(4) less than $90^{\circ}$ if $\mathrm{C}^{2}>\mathrm{A}^{2}+\mathrm{B}^{2}$
Correct options are -
- A1,2
- B1,2,3,4
- C2,3,4
- Correct answerD1,2,4
Hence, the correct answer is option: 'D'.