Q205 / 270 · NDA 2019 (Phase 1) · Mathematics
The two parabolas $y^2=4 a x$ and $x^2=4 a y$ intersect
- Correct answerAat two points on the line $y=x$
- Bonly at the origin
- Cat three points one of which lies on $y+x=0$
- Donly at (4a, 4a)
Solution
The parabolas $y^2=4 a x$ and $x^2=4 a y$
They intersect at $(0,0)$ and $(4 a, 4 a)$
These points lie on $y=x$
Hence, the correct answer is option: 'A'.