Q71 / 90 · JEE Main 2022 (29 Jun Shift 2) · Physics

The TV transmission tower at a particular station has a height of $125 m$ . For doubling the coverage of its range, the height of the tower should be increased by

Solution

Maximum distance covered is given by $d = \sqrt{2 R h}$ , here $R$ is the radius.

Now, to increase the length of radio transmission to $2$ times, $2 d = \sqrt{2 h^{'} R}$

Height of tower is $h^{'} = 4 h = 4 \times 125 = 500 m$

$\begin{aligned} \Delta H=h^{\prime}-h &=500-125 \\ &=375 \end{aligned}$

Hence, the correct answer is option: 'B'.