The truth table for the following logic circuit is

• Correct answer
  A

  $\left|\begin{array}{lll}A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{array}\right|$
• B

  $\left|\begin{array}{lll}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{array}\right|$
• C

  $\left|\begin{array}{lll}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{array}\right|$
• D

  $\left|\begin{array}{lll}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{array}\right|$

Solution

The truth table for the given logic circuit is

Hence, the correct answer is option: 'A'.