Q25 / 88 · NTA Abhyas (JEE Main) 2020 · Physics · Semiconductors

The transfer characteristic curve of a transistor, having input and output resistance 100 Ω and 100 kΩ respectively, is shown in the figure. The voltage and power gain, are respectively:
Figure

  • Correct answer
    A
    5×104, 2.5×106
  • B
    2.5×104, 2.5×106
  • C
    5×104, 5×106
  • D
    5×104, 5×105

Solution

Current gain β=ΔICΔIB= 5 ×10-3 100 ×10-6=50
Voltage gain (AV)=βRoutRin=50×100×103100=5×104
Power gain =AV×β=50×5×104=2.5×106

Hence, the correct answer is option: 'A'.

More Semiconductors Questions