The total number of divisors of the number N=2^5⋅3^4⋅5^10⋅7^6 that are of the form 4K+2, ∀K∈N is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: (B) 384. The required number is of the form 22K+1, i.e. it will contain exactly one power of 2. Also, we have to exclude 2 as K∈N. Number of required divisors =1⋅5⋅11⋅7-1=385-1=384

The total number of divisors of the number $N = 2^{5} \cdot 3^{4} \cdot 5^{10} \cdot 7^{6}$ that are of the form $4 K + 2, \forall K \in N$ is equal to

Solution

More Permutation Combination Questions

The total number of divisors of the number N=25⋅34⋅510⋅76 that are of the form 4K+2, ∀K∈N is equal to

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More Permutation Combination Questions

The total number of divisors of the number $N = 2^{5} \cdot 3^{4} \cdot 5^{10} \cdot 7^{6}$ that are of the form $4 K + 2, \forall K \in N$ is equal to