Q91 / 270 · NDA 2018 (Phase 2) · General Ability

The time period of oscillation of a simple pendulum having length $L$ and mass off the bob $m$ is given as $T$. If the length of the pendulum is increased to 4 L and the mass of the bob is increased to 2 m , then which one of the following is the new period of oscillation?

  • A
    T
  • Correct answer
    B
    2T
  • C
    4T
  • D
    T/2

Solution

Time period of a pendulum is given by $\mathrm{T}=2 \pi \sqrt{l / g}$ If length is now 41 then the new time period $\mathrm{T}_2$ will be $2 \pi \sqrt{4 l / g}$ Hence, the new time period of oscillation $\mathrm{T}_2=2 \mathrm{~T}$

Hence, the correct answer is option: 'B'.

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