The time-period of a simple pendulum of length $\sqrt{5} \mathrm{m}$ suspended in a car moving with uniform acceleration of $5 \mathrm{m }{\mathrm{s}}^{-2}$ in a horizontal straight road is $\left(g=10 \mathrm{m }{\mathrm{s}}^{-2}\right)$

• Correct answer
  A

  $\frac{2\pi }{\sqrt{5}} \mathrm{s}$
• B

  $\frac{\pi }{\sqrt{5}} \mathrm{s}$
• C

  $5\pi \mathrm{s}$
• D

  $4\pi \mathrm{s}$

Hence, the correct answer is option: 'A'.