Q89 / 180 · KCET 2019 · Mathematics

The third term of a G.P. is \( 9 \). The product of its first five terms is

A
\( 3^{9} \)
B
\( 3^{12} \)
C
\( 13^{5} \)
Correct answer
D
\( 3^{10} \)

Solution

(D)
Let \( \frac{a}{r^{2}} \cdot \frac{a}{r} \cdot a \cdot a r \cdot a r^{2} \) are in G.P., Given \( \mathrm{a}=9 \)
\( \therefore \) product \( =9^{5}=3^{10} \)

Hence, the correct answer is option: 'D'.

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