The temperature of water of mass 100 g is rasied from $24^{\circ} \mathrm{C}$ to $90^{\circ} \mathrm{C}$ by adding steam to it. The mass of the steam added is (Latent heat of steam $=540 \mathrm{cal} \mathrm{g}^{-1}$ and specific heat capacity of water $=1 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ )

• A

  10 g
• Correct answer
  B

  12 g
• C

  8 g
• D

  16 g

Hence, the correct answer is option: 'B'.