The temperature of the cold junction of thermocouple is 0^° C and the temperature of hot junction is T^° C . The emf is E=16 T-0.04 T^2 μ V . The inversion temperature T_i is

Correct answer: (D) 400^° C. As, E=16 T-0.04 T^2 At inversion temperature, E=0 ⇒ 16 T-0.04 T^2 =0 ⇒ T_i =16/0.04=400^° C

Q143 / 180 · JIPMER 2015 · Physics

The temperature of the cold junction of thermocouple is $0^{\circ} \mathrm{C}$ and the temperature of hot junction is $T^{\circ} \mathrm{C}$. The emf is $E=16 T-0.04 T^2 \quad \mu \mathrm{V}$. The inversion temperature $T_i$ is

A
$300^{\circ} \mathrm{C}$
B
$200^{\circ} \mathrm{C}$
C
$500^{\circ} \mathrm{C}$
Correct answer
D
$400^{\circ} \mathrm{C}$

Solution

As, $E=16 T-0.04 T^2$ At inversion temperature, $E=0$ $\begin{aligned} \Rightarrow \quad 16 T-0.04 T^2 & =0 \\ \Rightarrow \quad T_i & =\frac{16}{0.04}=400^{\circ} \mathrm{C}\end{aligned}$

Hence, the correct answer is option: 'D'.

The temperature of the cold junction of thermocouple is $0^{\circ} \mathrm{C}$ and the temperature of hot junction is $T^{\circ} \mathrm{C}$. The emf is $E=16 T-0.04 T^2 \quad \mu \mathrm{V}$. The inversion temperature $T_i$ is

Solution

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