Q9 / 9 · NTA Abhyas (JEE Main) 2020 · Physics · Kinetic Theory of Gases

The temperature of an ideal gas is increased from 100 K to 400 K . If the rms speed of the gas molecule is V at 100 K , then at 400 K it becomes

  • Correct answer
    A
    2V
  • B
    4V
  • C
    0.5V
  • D
    V

Solution

∵  rms speed of molecule Vrms∝T

for T=100 K

Vrms1∝100

For T=400 K

Vrms2∝400

therefore, Vrms1Vrms2=100400

or VVrms2=12

or Vrms2=2V

Hence, the correct answer is option: 'A'.

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