Q80 / 180 · NEET 2015 (Phase 2) · Chemistry

The sum of coordination number and oxidation number of metal M in the complex $[M {(e n)}_{2} (C_{2} O_{4})] C l$ (Where en is ethylenediamine) is:

Correct answer
A
9
B
6
C
7
D
8

Solution

$[M {(e n)}_{2} (C_{2} O_{4})] C l$

Oxidation state of M = +3

en and oxalate ion are bidentate ligands. So, Coordination number of M = 6

Sum of oxidation state + Coordination number = 3 + 6 = 9

Hence, the correct answer is option: 'A'.

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