Q154 / 200 · Manipal (MET) 2014 · Physics

The strain stress curves of three wires of different materials are shown in the figure. $P$, $Q$ and $R$ are the elastic limits of the wires. The figure shows that Figure

  • A
    elasticity of wire $P$ is maximum
  • B
    elasticity of wire $Q$ is maximum
  • Correct answer
    C
    tensile strength of $R$ is maximum
  • D
    None of the above is true

Solution

On the graph stress is represented on $x$-axis and strain $y$-axis So from the graph $y=\cot \theta=\frac{1}{\tan \theta} \propto \frac{1}{\theta}$ [where, $\theta$ is the angle from stress axis] $\therefore \quad Y_P \lt Y_Q \lt Y_R \quad\left[\text { As } \theta_P \lt \theta_Q \lt \theta_R\right]$
We can say that elasticity of wire $P$ is minimum and $R$ is maximum.

Hence, the correct answer is option: 'C'.

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