Q93 / 197 · NEET 2009 (Mains) · Chemistry

The state of hybridization of $\mathrm{C}_2, \mathrm{C}_3, \mathrm{C}_5$ and $\mathrm{C}_6$ of the hydrocarbon - Figure
is in the following sequence :

  • A
    $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$ and $\mathrm{sp}^2$
  • Correct answer
    B
    $\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}^2$ and $\mathrm{sp}^3$
  • C
    $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}^2$ and $\mathrm{sp}$
  • D
    $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^2$ and $\mathrm{sp}^3$

Solution

$$ \begin{aligned} & \mathrm{C}_2 \text { having } \rightarrow 2-\sigma \text { bond } \rightarrow \mathrm{sp} \\ & \mathrm{C}_3 \text { having } \rightarrow 4-\sigma \text { bond } \rightarrow \mathrm{sp}^3 \\ & \mathrm{C}_5 \text { having } \rightarrow 3-\sigma \text { bond } \rightarrow \mathrm{sp}^2 \\ & \mathrm{C}_6 \text { having } \rightarrow 4-\sigma \text { bond } \rightarrow \mathrm{sp}^3 \end{aligned} $$

Hence, the correct answer is option: 'B'.

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