Q24 / 90 · JEE Main 2015 (04 Apr) · Chemistry

The standard Gibbs energy change at 300 K for the reaction 2A⇌B+C is 2494.2 J. At a given time, the composition of the reaction mixture is A=12, B=2 and C=12 . The reaction proceeds in the: [R=8.314 J/K-mol ,  e=2.718]  {Given antilog (-0.44)=0.36}

  • A
    Reverse direction because Q<KC
  • B
    Forward direction because Q>KC
  • Correct answer
    C
    Reverse direction because Q>KC
  • D
    Forward direction because Q<KC

Solution

Δ G ∘ = - RT ln K C

2494.2 = - 8.314 × 300 ln K C

2494.2 = - 8.314 × 300 × 2.303 log K C

- 2494.2 2.303 × 300 × 8.314 = - 0.44 = log K C

log KC=-0.44

K C = 0.36

Q=[B][C][A]2=2×12122=4

Q>KC, reaction will shift in reverse direction.

Hence, the correct answer is option: 'C'.

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