Q46 / 180 · KCET 2010 · Chemistry

The standard emf of galvanic cell involving 3 moles of electrons in its redox reaction is $0.59 \mathrm{~V}$. The equilibrium constant for the reaction of the cell is

  • A
    $10^{25}$
  • B
    $10^{20}$
  • C
    $10^{15}$
  • Correct answer
    D
    $10^{30}$

Solution

$\begin{aligned} \mathrm{E}_{\text {cell }}^{\circ} &=\frac{0.0591}{\mathrm{n}} \log \mathrm{K}_{\mathrm{c}} \\ 0.59 &=\frac{0.0591}{3} \log \mathrm{K}_{\mathrm{c}} \\ \frac{0.59 \times 3}{0.059} &=\log \mathrm{K}_{\mathrm{c}} \\ \therefore \quad \log \mathrm{K}_{\mathrm{c}} &=30 \\ \mathrm{~K}_{\mathrm{c}} &=\text { antilog } 30 \\ &=10^{30} \end{aligned}$

Hence, the correct answer is option: 'D'.

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