The Spin only magnetic moment value of square planar complex $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_2\mathrm{Cl}\left({\mathrm{NH}}_2{\mathrm{CH}}_3\right)\right]\mathrm{Cl}$ is _______ B.M. (Nearest integer)
( Given atomic number for $\mathrm{Pt}=78)$

Spin only magnetic moment can be calculated by the following formula
Magnetic moment =$\sqrt{\mathrm{n}(\mathrm{n}+2)}$
Where, n is number of unpaired electrons.

In the given compound, ${\mathrm{Pt}}^{2+}\left({\mathrm{d}}^8\right)$

${\mathrm{Pt}}^{2+}\to {\mathrm{dsp}}^2$ hybridization and have no unpaired electrons..

$\therefore$ Magnetic moment

 $$\begin{gathered} =\sqrt{\mathrm{n}(\mathrm{n}+2)} \\ =\sqrt{0(0+2)} \\ =0 \end{gathered}$$