Q73 / 90 · JEE Main 2024 (31 Jan Shift 2) · Physics

The speed of sound in oxygen at S.T.P. will be approximately:
(Given, $R = 8.3 J K^{- 1}, γ = 1.4)$

Solution

The speed of sound is given by,

$v = \sqrt{\frac{γ R T}{M}} = \sqrt{\frac{1.4 \times 8.3 \times 273}{32 \times 10^{- 3}}}$

$= 314.8541 ≃ 315 m s^{- 1}$

Nearest answer given in the option is $310 m s^{- 1}$ .

Hence, the correct answer is option: 'A'.