Q76 / 90 · JEE Main 2019 (09 Apr Shift 2) · Physics

The specific heats, Cp and Cv of a gas of diatomic molecules, A, are given (in units of J mol-1 K-1 ) by 29 and 22, respectively. Another gas of diatomic molecules, B, has the corresponding values 30 and 21. If they are treated as ideal gases, then:

  • A
    A has one vibrational mode and B has two
  • Correct answer
    B
    A has a vibrational mode but B has none.
  • C
    Both A and B have a vibrational mode each.
  • D
    A is rigid but B has a vibrational mode.

Solution

For A :
R=Cp-Cv=29-22=7
Cv=fR2
⇒22=f×72
⇒f=447=6.3
⇒f≈6

(5 rotational + translational, 1 vibrational)


For B :
R=Cp-CV=30-21=9
Cv=fR2=21
⇒f=21×29=429=4.66≃5
∴ f≃5

 (5 rotational + transitional, 0 vibrational)

Hence, the correct answer is option: 'B'.

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