Q4 / 160 · AP EAMCET 2018 (22 Apr Shift 2) · Chemistry

The species, which has the bond order same as that of $\mathrm{F}_2$ molecule is

  • A
    $\mathrm{O}_2^{+}$
  • Correct answer
    B
    $\mathrm{O}_2^{2-}$
  • C
    $\mathrm{O}_2$
  • D
    $\mathrm{N}_2^{+}$

Solution

MO for the fluorine molecule, the 14 valence electrons of the fluorine atoms fill 4 bonding and 3 anti-bonding orbital thus bond order is 1 . Bond order $$ =\frac{\text { bonding electrons }- \text { anti }- \text { bonding electrons }}{2} $$ In the same way $\mathrm{O}_2^{2-}$ has $2 \times(6)+2=14 e^{-}$ So, bond order is 1 .

Hence, the correct answer is option: 'B'.

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