Q88 / 225 · JEE Main 2002 · Mathematics

The solution of the equation $\frac{d^2 y}{d x^2}=e^{-2 x}$

  • A
    $\frac{e^{-2 x}}{4}$
  • Correct answer
    B
    $\frac{e^{-2 x}}{4}+c x+d$
  • C
    $\frac{1}{4} e^{-2 x}+c x^2+d$
  • D
    $\frac{1}{4} e^{-4 x}+c x+d$

Solution

$\frac{d^2 y}{d x^2}=e^{-2 x} ; \frac{d y}{d x}=\frac{e^{-2 x}}{-2}+c ; y=\frac{e^{-2 x}}{4}+c x+d$

Hence, the correct answer is option: 'B'.

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