Q46 / 105 · NTA Abhyas (JEE Main) 2020 · Mathematics · Differential Equations

The solution of the differential equation ysin2xdy+sin⁡xcos⁡xy2dx=xdx is (where C is the constant of integration)

  • A
    sin2x⋅y=x2+C
  • Correct answer
    B
    sin2x⋅y2=x2+C
  • C
    sinx⋅y2=x2+C
  • D
    sin2x⋅y2=x+C

Solution

The given equation is sin2x2ydy+2sin⁡xcos⁡xdxy2=2xdx
or dsin2x⋅y2=2xdx
On integrating, we get
 sin2x⋅y2=x2+C

Hence, the correct answer is option: 'B'.

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