Q98 / 150 · MHT CET 2026 (15 April Shift 1) · Mathematics
The solution of the differential equation $\dfrac{dy}{dx} = e^{x-y} + x^2 e^{-y}$ is...
- A$y = e^x + c$
- B$e^y = e^x + x^3 + c$
- Correct answerC$e^y = e^x + \dfrac{x^3}{3} + c$
- D$e^y = e^x + 2x + c$
Solution
The given differential equation is $\dfrac{dy}{dx} = e^{x-y} + x^2 e^{-y}$
This can be rewritten by factoring out $e^{-y}$ as $\dfrac{dy}{dx} = e^{-y}(e^x + x^2)$
Separating the variables, we get $e^y dy = (e^x + x^2) dx$
Integrating both sides, we get $\int e^y dy = \int (e^x + x^2) dx$
$e^y = e^x + \dfrac{x^3}{3} + c$
Answer: $e^y = e^x + \dfrac{x^3}{3} + c$
This can be rewritten by factoring out $e^{-y}$ as $\dfrac{dy}{dx} = e^{-y}(e^x + x^2)$
Separating the variables, we get $e^y dy = (e^x + x^2) dx$
Integrating both sides, we get $\int e^y dy = \int (e^x + x^2) dx$
$e^y = e^x + \dfrac{x^3}{3} + c$
Answer: $e^y = e^x + \dfrac{x^3}{3} + c$
Hence, the correct answer is option: 'C'.