Q64 / 160 · JIPMER 2012 · Chemistry

The solubility product of $\mathrm{Hg}_2 \mathrm{I}_2$ is equal to

  • A
    $\left[\mathrm{Hg}_2^{2+}\right]\left[\mathrm{I}^{-}\right]$
  • B
    $\left[\mathrm{Hg}^{2+}\right]\left[\mathrm{I}^{-}\right]$
  • Correct answer
    C
    $\left[\mathrm{Hg}_2^{2+}\right]\left[\mathrm{I}^{-}\right]^2$
  • D
    $\left[\mathrm{Hg}^{2+}\right]\left[\mathrm{I}^{-}\right]^2$

Solution

$\mathrm{Hg}_2 \mathrm{I}_2(s) \rightleftharpoons \mathrm{Hg}_2^{2+}+2 \mathrm{I}^{-}$ $\therefore \quad K_{s p}=\left[\mathrm{Hg}_2^{2+}\right]\left[\mathrm{I}^{-}\right]^2$

Hence, the correct answer is option: 'C'.

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