Q60 / 180 · NEET 2018 · Chemistry

The solubility of BaSO4 in water is 2.42×10-3 gL-1 at 298 K. The value of its solubility product Ksp will be

(Given- the molar mass of BaSO4=233 g mol-1)

  • A
    1.08×10-14 mol2 L-2
  • B
    1.08×10-12 mol2 L-2
  • Correct answer
    C
    1.08×10-10 mol2 L-2
  • D
    1.08×10-8 mol2 L-2

Solution

Solubility of BaSO4=2.42×10-3 gL-1

∴ s=2.42×10-3233=1.038×10-5 mol L-1

Ksp=s2=1.038×10-52

=1.08×10-10 mol2 L-2

Hence, the correct answer is option: 'C'.

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