The sides of a triangle are $x=2, y+1=0$ and $x+2 y=4$. Its circumcentre is

• Correct answer
  A

  $(4,0)$
• B

  $(2,-1)$
• C

  $(0,4)$
• D

  $(2,3)$

Solution

The vertices are $(2,-1),(6,-1),(2,1)$ forming a right angled triangle. Circumcentre is the mid-point of the hypotenuse,

i.e., $\quad\left(\frac{6+2}{2}, \frac{1-1}{2}\right)=(4,0)$

Hence, the correct answer is option: 'A'.