Q129 / 150 · MHT CET 2023 (09 May Shift 2) · Physics
The side of a copper cube is $1 \mathrm{~m}$ at $0^{\circ} \mathrm{C}$. What will be the change in its volume, when it is heated to $100^{\circ} \mathrm{C}$ ? $\left[\alpha_{\text {copper }}=18 \times 10^{-6} /{ }^{\circ} \mathrm{C}\right]$
- A$45 \times 10^{-4} \mathrm{~m}^3$
- Correct answerB$54 \times 10^{-4} \mathrm{~m}^3$
- C$34 \times 10^{-4} \mathrm{~m}^3$
- D$64 \times 10^{-4} \mathrm{~m}^3$
Solution
In volumetric expansion for a cube, Change in volume $\Delta \mathrm{V}=\mathrm{V} 3 \alpha \Delta \mathrm{T}$
$\begin{aligned}
& \Delta V=3 \times 18 \times 10^{-6} \times 100 \\
& \Delta V=54 \times 10^{-4} \mathrm{~m}^3
\end{aligned}$
Hence, the correct answer is option: 'B'.