The shortest wavelength of the Brackett series of a hydrogen like atom (Atomic number =Z ) is the same as the shortest wavelength of the Balmer series…

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The shortest wavelength of the Brackett series of a hydrogen like atom (Atomic number =Z ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of Z is

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Correct answer: (A) 2. Shortest wavelength corresponds to maximum energy therefore transitions are from infinity to n=4 and n=2 respectively. Z^213.6/16=13.6/4 Z^2=4 or Z=2

The shortest wavelength of the Brackett series of a hydrogen like atom (Atomic number $= Z$ ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of $Z$ is

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