Q10 / 155 · WBJEE 2017 · Chemistry

The shape of $XeF_{5}^{-}$ will be

  • A
    square pyramid
  • B
    trigonal bipyramidal
  • Correct answer
    C
    planar
  • D
    pentagonal bipyramid

Solution

Shape of XeF $\rightarrow$ Figure The Xe show $s p^{3} d^{3}$ -hybridisation in $XeF^{-}_{5}$, Thus, its geometry is Pentagonal-bipyramidal. But, number of electron pair $=\frac{8+5+1}{2}=7$ Number of bond pair $=5^{2},$ number of lone pair $=2$ A lot of electrons are present at axil position and all bonds are in same plane. Hence, the shape is planar.

Hence, the correct answer is option: 'C'.

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