Q61 / 180 · KCET 2016 · Mathematics

The Set A has \( 4 \) elements and the Set B has \( 5 \) elements then the number of injective mappings
that can be defined from A to B is

A
\( 144 \)
B
\( 72 \)
C
\( 60 \)
Correct answer
D
\( 120 \)

Solution

Given that, \( n(A)=4 \) and \( n(B)=5 \).
Number of injective mappings that can be define from \( A \) to \( B \) is given by
\( (n(B)) !=5 !=120 \)

Hence, the correct answer is option: 'D'.

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