Q172 / 270 · NDA 2013 (Phase 2) · Mathematics
The roots of the equation $x^2-8 x+16=0$
- Aare imaginary
- Bare distinct and real
- Correct answerCare equal and real
- Dcannot be ascertained
Solution
$\begin{aligned}
\operatorname{Discriminant}(\mathrm{D}) & =b^2-4 a . c \\
& =(-8)^2-4.1 \cdot 16 \\
& =64-64=0 \\
\mathrm{for \quad D} & =0,
\end{aligned}$
two roots are real & equal.
Hence, the correct answer is option: 'C'.