The role of fluorspar during the electrolysis of molten alumina is
$\left(\mathrm{i}\right)$ To reduce the melting point
$\left(\mathrm{i}\mathrm{i}\right)$ To increase conductivity
$\left(\mathrm{i}\mathrm{i}\mathrm{i}\right)$ As a seeding agent

• A

  All are correct
• Correct answer
  B

  Only $\left(\mathrm{i}\right)$ is correct
• C

  $\left(\mathrm{i}\right),\mathrm{}\left(\mathrm{i}\mathrm{i}\right)$ are correct
• D

  $\left(\mathrm{i}\right),\mathrm{}\left(\mathrm{i}\mathrm{i}\mathrm{i}\right)$ are correct

Hence, the correct answer is option: 'B'.